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          Д(sh)W֪Rcĸ

          rg2021-01-19 09:23:13 Д(sh)W ҪͶ

          Д(sh)W֪Rcĸ

          Zһ˵ؕIؓسɷ@ƺƷϵһСP(gun)ڳД(sh)WČWϣgӭxHP(gun)֪RՈP(gun)עCNFLAWW(wng)ęĿ!

          Д(sh)W`֪Rcĸ

          ĸ

          I.ĸdžʽ

          :√a/√b=√a×√b/√b×√b=√ab/b

          II.ĸǶʽ

          ƽʽ

          1/√a+√b=√a-√b/(√a+√b)(√a-√b)=√a-√b/a-b

          ʽзĸܺи̖Ҫ׃?yu)IJС?/p>

          ʽ\

          1\㷨t(m,n(sh))

          (1)a×a=a²;

          (2)a²÷a=a;(a≠0)

          (3)(a)²=a²

          (4)(ab)²=a²b²

          2ʽ\()

          3˷ʽ

          (a+b)(a-b)=a^2-b^2

          (a+b)^2=a^2+2ab+b^2

          (a-b)^2=a^2-2ab+b^2

          (a+b)( a^2-ab+b^2) =a^3+b^3

          (a-b)( a^2+ab+b^2) =a^3-b^3

          ()ʽʽֽ

          һʽɎׂʽķeʽʽֽ

          1ṫʽ;

          2ʽ

          a^2-b^2=(a+b)(a-b)

          a^2+2ab+b^2=(a+b)^2

          a^2-2ab+b^2=(a-b)^2

          a^3+b^3=(a+b)(a^2-ab+b^2)

          a^3-b^3=(a-b)(a^2+ab+b^2)

          3ʮ˷ֽʽ

          ax+bx+c=a(x-x1)(x-x2)

          Д(sh)W֪RcĸP(gun)£

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